Finding the Sum of a Series: Proving Solutions

  • Thread starter Thread starter negatifzeo
  • Start date Start date
  • Tags Tags
    Series Sum
negatifzeo
Messages
66
Reaction score
0

Homework Statement


I'm having trouble finding the sum of a series. I am able to perform the task for "geometric" series, where there is an "a" or an "r" value. But take the following problem for instance:
<br /> \sum_{n=2}^\infty \frac{1}{4^n}<br />
I'm just not sure how to approach this problem and "prove" a solution. I know that since the numbers being added are getting smaller and smaller this sum likely converges, and I suspect it converges at (1/4). But again, how do I show this?

Homework Equations





The Attempt at a Solution

 
Physics news on Phys.org
That is a geometric series. It's (1/4)^n.
 
Ah, indeed it is. I don't know how I missed that, I guess this post can be deleted.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...

Similar threads

Back
Top