Finding the Sum of Perpendiculars in a 24-Sided Polygon Inscribed in a Circle

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The discussion revolves around calculating the sum of perpendiculars dropped from the vertices of a regular 24-sided polygon inscribed in a circle to a diameter. Participants explore the use of trigonometric identities to express the lengths of these perpendiculars in terms of the circle's radius. The key insight is that the height of each perpendicular corresponds to the sine of specific angles derived from the polygon's geometry. A formula involving the sum of sines is proposed to facilitate the calculation. The conversation emphasizes the importance of understanding trigonometric relationships to solve the problem effectively.
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Homework Statement



There is a regular 24 sided polygon inscribed in a circle. A diameter is drawn and perpendiculars are dropped from all the vertices on that side of the diameter. Find the sum of the lengths of the perpendiculars.

The Attempt at a Solution



I came across this problem and I have no clue how to approach it. I'm looking for a point in the right direction. Thanks for the help!
 

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hi armolinasf!

well, what formula are you starting with? :smile:
 
No formula was given. It was at the end of a section on trig identities, specifically using them to sum trig series.
 
You have to find the formula. You have studied trigonometry haven't you?

ehild
 
My first instinct was to write something like S=r+2(l1+l2+l3+l4+l5), where l is the length of each chord. Should I be looking for a way to express each l in terms of r?
 
hi armolinasf! :smile:

yes, and the various angles (nπ/12)
 
Yeah i finally realized that the height of each perpendicular is equal to the sine of the angles...So here my sum:

S=r+2r[sin(pi/12)+sin(pi/6)+sin(pi/4)+sin(pi/3)+sin(5pi/12)]
 
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