Finding the Total Charge of a Non-Uniformly Charged Disc

AI Thread Summary
To find the total charge of a non-uniformly charged disc with radius R, one half has a charge density of +2σ and the other half has -σ. The initial approach suggests splitting the disc into two parts to calculate the charge separately, but there is uncertainty about whether "half" refers to surface area or radius. Clarification is needed on the definition of the halves in the problem statement, as it impacts the calculation. The discussion highlights the complexity of integrating charge density over a non-uniform area. Ultimately, understanding the geometry of the charge distribution is crucial for an accurate solution.
Hatyk
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Homework Statement


I have a disc with radius R. One half has the charge density of +2σ and the other half has −σ. The task is to find the total charge of the disc.

Homework Equations


dQ=ρ2πr^2 I would use this equation if the charge density was uniform

The Attempt at a Solution


My first idea was to split the disc in the middle and find the total charge of each part separately and then add them up. Thinking about it now, this solution feels wrong. What is the correct solution?
 
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Well, in my opinion the statement of problem not say if the half is the half of radius or the half of surface. My intuition says the half of surface, but you can make the two cases
 
Statement of the problem is not complete. Which two halves are we talking about?
 
Hatyk said:

Homework Statement


I have a disc with radius R. One half has the charge density of +2σ and the other half has −σ. The task is to find the total charge of the disc.

Homework Equations


dQ=ρ2πr^2 I would use this equation if the charge density was uniform

The Attempt at a Solution


My first idea was to split the disc in the middle and find the total charge of each part separately and then add them up. Thinking about it now, this solution feels wrong. What is the correct solution?
I see nothing wrong with your assumption. I'll go on a limb and say it doesn't matter if the charges are all +2s on one side and -s on the obverse side, vs. each side has half +2s and the other half -s.
 
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How about half the radius with +2σ and the other half with -σ?
 
Chandra Prayaga said:
How about half the radius with +2σ and the other half with -σ?
Personally I'd have some difficulty justifying that given how the area of a disk varies with the radius :smile:
 
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