Finding the Vertical Tangent Line of x3 + xy - y2 = 10 Curve

sonofjohn
Messages
76
Reaction score
0
The curve defined by x3 +xy - y2 = 10 has a vertical tangent line when x = ?

To find when the tangent line is vertical, could I find when the slope is undefined for the original function? The way I previously tried this problem was by taking the first derivative and then finding when x = 0. That is one of the multiple choice answers but that cannot be right, for that would find the horizontal tangent and not the vertical tangent line.
 
Physics news on Phys.org
Now that I think about it couldn't I find where the slope is undefined by finding where the first derivative is undefined?

If I have

dy/dx = (-3x^2 - x)/(x-2y)

could I set the denominator = 0 and solve?
 
Yes, of course. I was wondering why you were setting "x= 0" before.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top