Finding three roots of equation

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1. ei∏/3z3 = 1/(1+i)


3. Wasn't sure at all how to start...Attempted to rearrange, bringing the exponential to the right and expanding using Euler's theorem, but it didn't work.

I'll be really grateful to anyone generous enough to help :) thanks
 
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mainguy said:
1. ei∏/3z3 = 1/(1+i)


3. Wasn't sure at all how to start...Attempted to rearrange, bringing the exponential to the right and expanding using Euler's theorem, but it didn't work.

I'll be really grateful to anyone generous enough to help :) thanks

I would try to express the right side in polar form first. I.e. as a exponential.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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