Finding total current for series capacitors

AI Thread Summary
To find the total current for capacitors in series, it's important to note that in DC circuits, the question is irrelevant, while in AC circuits, frequency must be specified. The total current through series capacitors is consistent across each capacitor. To calculate the combined capacitance of capacitors in series, treat them as a single equivalent capacitor. The reactance of a capacitor can be used to determine current using the formula Current = V / X, where V represents the voltage and X is the reactance. Understanding this relationship clarifies the calculation process for AC circuits involving series capacitors.
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I guess the title basically explains it. I'm reading over some circuits and can't figure out how to find total current for a circuit with capacitors in series.
 
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For DC it's meaningless to ask the question. For AC you need to specific something about the frequency or frequencies of relevance.
 
The total current through series capacitors is the same as through each of them.

The combined capacitance of capacitors in series is:
fa34ce461e6988fd973081401cc9790c.png


So, if you calculate this to get the combined capacitance of the series capacitors, you can then regard the result as one capacitor.

The reactance X of a capacitor is:
331f118c5d84ff180213e4ed2a95674a.png


So, you can calculate the current from this formula:
Currrent = V / X
where V is the peak, or the peak to peak, or the RMS voltage of a sinewave. The current will then be the peak, peak to peak, or RMS value of the AC current.
 
Thanks Vk6kro. I actually finally figured it out I had the reactance but for some reason just wasn't thinking to use V/X I felt stupid once I realized that. Thanks again
 
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