Finding v0 in an Ideal Op-Amp Circuit

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Discussion Overview

The discussion revolves around analyzing an ideal op-amp circuit to derive an expression for the output voltage (v0) in terms of input voltages (vA, vB) and resistance values. The conversation includes attempts to apply Kirchhoff's voltage law (KVL) and explore the characteristics of ideal op-amps, particularly in the context of input impedance and voltage relationships.

Discussion Character

  • Homework-related
  • Technical explanation
  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • One participant attempts to express v1 in terms of v0 using the formula v1 = R1/(R1 + R2) * v0 but struggles to find another expression for v1.
  • Another participant asks about the basic rules governing ideal op-amps, specifically referencing the voltage rule.
  • There is confusion regarding the application of KVL and the implications of the summing point constraint at the op-amp inputs.
  • Some participants assert that the voltage at each input of the op-amp is equal (V1), which is a characteristic of ideal op-amps.
  • Questions arise about the input impedance of the op-amp, with one participant suggesting it could be zero or infinity, depending on the context.
  • One participant references a source that states the input impedance (Rin) is zero, while another questions this conclusion, arguing that it should be infinity since no current enters the op-amp inputs.
  • A later reply provides a calculation for V1 based on the input voltages and resistances, leading to a formula for v0.

Areas of Agreement / Disagreement

Participants express differing views on the input impedance of the op-amp, with no consensus reached on whether it is zero or infinity. The discussion also reflects varying levels of understanding regarding the application of KVL and the characteristics of ideal op-amps.

Contextual Notes

Some assumptions regarding the circuit configuration and the definitions of terms like input impedance are not fully clarified. The discussion includes unresolved mathematical steps and varying interpretations of the op-amp rules.

surajalok
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Homework Statement


Analyze the ideal op-amp circuit shown in figure to find an expression for v0 in terms of vA,vB and the resistance values.


Homework Equations


if i label the voltage across R1 as V1
then vi know that v1=R1/(R1+R2) *v0
but i need one more expression for v1.
i tried to use kvl in the lope (with Va,Ra and R1) but couldn't solve because of resistance Ra



The Attempt at a Solution

 

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What are the two basic rules governing ideal Op-Amps? (Hint: Use the voltage one, not the current one)
 
what do u meen with use Use the voltage one?
i tried using kvl on all the loops but coudn't solve.
current goin into the + on the amp =0 and voltage is 0 between + and - on the amp. summing point constraint.
 
The voltage at each of the op-amp's inputs is = V1. It's just a fact about ideal op-amps.
 
is there any way to show that
How about noninvering amp?
But then should i use KVL at amp node=
 
The current going into each input = 0 and the voltage is the same at each input. It's true for inverting and non-inverting.
 
And one more question in an amplifing circuit is the input impedance =0 or is is it infinity
or does it depend on the other facts.
We have a voltage source directy connected to + or - on the amp
but it woulden't be op-amp's inputs is = V1. for noninvering amp because R1 doen't exist in non inverting.
 
Well, I think I have given you too many free answers haha.

Just use Ohm's law and you can figure out the input impedance. I = V/R. To get 0 current, your R must be ?

Then you would have the same voltage on the other input if it is directly connected, they are always the same.
 
  • #11
i just want to know why the get Rin =0
because WesleyPipes said i=v/R
I=0 if R=--->infinity or if v=0
we know that v is zero
but R can't be zero
 
  • #12
Calculation is simple.

Va-V1)/Ra + Vb-V1)/Rb = 0
Solving, V1= [(Va/Ra) + (Vb/Rb)] / [(1/Ra) + (1/Rb)]

Now, Vo = [1+ (R2/R1)]V1
Substitute and you will get the answer.
 

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