Finding value of polynomial using the remainder theorem

frozenbananas
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Homework Statement



Find the indicated value of the polynomial using the Remainder Theorem
p(x)=2x^3-2x^2+11x-100; find p(3)

Homework Equations



p(x)=2x^3-2x^2+11x-100

The Attempt at a Solution


Synthetic division
3] 2 -2 11 -100
6 12 69
2 4 23 [-31
answer: p(3)=-31

im not sure because i just followed the example in the book and applied it to this problem but the one in the book had another polynomial it was divided by to find the remainder. please help me, i have a test in the morning and I am freaking out like crazy, thanks!
 
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Yes, that is correct. Esssentially what you have shown is that
2x^3- 2x^2+ 11x- 100= (x- 3)(2x^2+ 4x+ 23)- 31

Putting x= 3 makes x- 3= 0 so whatever the number in the second paretheses is, the value is just -31.

Certainly, it wouldn't have been that hard for you to check it yourself by evaluating directly: 3^3= 27 so 2(3^3)= 2(27)= 54. -2(3^2)=-2(9)= -18. 11(3)= 33 so the whole thing is 54- 18+ 33- 100= 36+ 33- 100= 69- 100= -31.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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