mateomy
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We're going over the intro stuff to integration and we are being asked to find the value of the sums...
Here's the problem I am getting stuck on...
<br /> \sum_{i=1}^{n} (i^2 + 3i + 4)<br />
I know that I have to separate the individual sums, so I put it into this form...
<br /> \sum_{i=1}^{n} i^2 + 3\sum_{i=1}^{n} i + \sum_{i=1}^{n} 4<br />
And then I know the individual forms of the Riemann sums of i^2 and i, etc.
<br /> \sum_{i=1}^{n} i^2 = \frac{n(n+1)(2n+1)}{6} etc, etc...<br />
am I just adding these together as if they were fractions (finding common denominators, etc)?
Here's the problem I am getting stuck on...
<br /> \sum_{i=1}^{n} (i^2 + 3i + 4)<br />
I know that I have to separate the individual sums, so I put it into this form...
<br /> \sum_{i=1}^{n} i^2 + 3\sum_{i=1}^{n} i + \sum_{i=1}^{n} 4<br />
And then I know the individual forms of the Riemann sums of i^2 and i, etc.
<br /> \sum_{i=1}^{n} i^2 = \frac{n(n+1)(2n+1)}{6} etc, etc...<br />
am I just adding these together as if they were fractions (finding common denominators, etc)?