How to Calculate Voltage for a Capacitor Charged by a Constant Current?

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To calculate the voltage across a 60-microfarad capacitor charged by a 6mA current for 10 seconds, the formula V=1/C ∫i dt is used. The integral of the current with respect to time needs to be solved, and the result is then multiplied by 1/C. It's important to note that the initial voltage across the capacitor may not be zero, which can affect the final calculation. The discussion indicates that the calculations yield a neat, even result. Proper integration and consideration of initial conditions are crucial for an accurate voltage determination.
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1.
The question asks, to what voltage would a 60-microfarad capacitor be charged by a 6mA current lasting 10 seconds?


2.
I used this formula, V=1/C ∫i dt
but I'm not sure how to solve the integral.
Thanks for any help
 
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Your integral looks good. You just need to integrate the current with respect to time and multiply by 1/C.

Note the problem does not state that the initial voltage across the capacitor is zero.
 
Last edited:
If I did this correctly, I got a very nice even number - VERY even.
 

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