Finding volume using triple integral

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SUMMARY

The discussion focuses on calculating the volume of a solid defined by the inequalities and equations: x² + y² > 1, x² + z² = 1, and x² + y² = 1. The approach involves using a triple integral with the integrand set to 1, specifically employing the differential volume element dz r dr dθ. The user suggests evaluating the volume in the first quadrant and then multiplying the result by 8 to account for symmetry. A recommendation is made to reconsider the coordinate system for integration to simplify the process.

PREREQUISITES
  • Understanding of triple integrals in calculus
  • Familiarity with polar and cylindrical coordinate systems
  • Knowledge of volume calculation techniques
  • Basic algebraic manipulation of inequalities and equations
NEXT STEPS
  • Study the application of cylindrical coordinates in triple integrals
  • Learn how to set up and evaluate triple integrals for volume
  • Explore the conversion between Cartesian and polar coordinates
  • Investigate symmetry in volume calculations to simplify integration
USEFUL FOR

Students studying calculus, particularly those focusing on multivariable integration, as well as educators and tutors looking for examples of volume calculation using triple integrals.

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Homework Statement



I need to find the volume of a solid formed by the following equations:
x^2+y^2 > 1
x^2+z^2 = 1
x^2 + y^2 =1

The Attempt at a Solution



I know that it is a triple integral and the integrand is 1.
I also know that I need to use dzrdrd[tex]\theta[/tex].

I believe that you need two integrals, one with z going from 0 to sqrt (1-costheta^2) and the other with z going from 0 to sqrt (1-sintheta^2). I only want to find the volume in the first quadrant then I will multiply by 8.
 
Last edited:
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Have you been told you need to use [tex]dz rd rd\theta[/tex] ?

If so then rethink you co-ordinate system when integrating, and look at your functions and see if you can convert them into any other coordinate system you know of
 

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