Finding Volume with Cylindrical Shells

  • Thread starter Thread starter silverbell
  • Start date Start date
  • Tags Tags
    Cylindrical Volume
silverbell
Messages
9
Reaction score
0

Homework Statement



Using cylindrical shells, find the volume obtained by rotating the region bounded by the given curves about the x-axis.

x= (y^2) +1

x= 0

y=1

y=2

Homework Equations



2∏ ∫ rh



The Attempt at a Solution



2∏ ∫ from 1 to 2 (y^2) + 1

I'm not sure where to go from here. :S Please help.
 
Physics news on Phys.org
silverbell said:

Homework Statement



Using cylindrical shells, find the volume obtained by rotating the region bounded by the given curves about the x-axis.

x= (y^2) +1

x= 0

y=1

y=2

Homework Equations



2∏ ∫ rh



The Attempt at a Solution



2∏ ∫ from 1 to 2 (y^2) + 1

I'm not sure where to go from here. :S Please help.

Start with a sketch of the region that is being rotated. Then draw a sketch of the solid that is formed.
 
I drew a sketch. I'm not sure what do do about the radius part. I know y= 2 is the higher radius along the x-axis. And y= 1 is the lower radius along the x-axis. Do I subtract the radius minus function?
 
The expression for incremental volume (the volume of a thin horizontal strip that is revolved around the x-axis) is 2\pi * radius * width of strip * Δy.

The radius varies from what to what?
How wide is a typical strip?
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top