Finding Wavelength of mosquito wings

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To find the wavelength of the sound produced by a mosquito flapping its wings at 600 Hz, the speed of sound (approximately 344 m/s) is used in the formula λ = v/f. Substituting the values, λ = 344 m/s / 600 Hz results in a wavelength of approximately 0.573 meters. The discussion highlights the importance of rearranging the equation correctly to solve for wavelength. The final answer confirms the wavelength as 0.573 meters. Understanding the relationship between frequency and wavelength is crucial in sound wave calculations.
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How do you find the wavelength of this: A mosquito flaps its wings 600 vibrations per second ( it is this motion that produces the annoying 600-Hz buzz). How far does the sound travel between wing beats? In other words, find the wavelength of the mosquito’s sound.

Thanks
 
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Look up the speed of sound V. Then L=V/600.
 
v=frac{f}{lambda}
 
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so is the wave length...

so I substituted and got 344=600*(n)...how do I do the rest confused...how do I rearrange the equation?
 
oh its .6 meters right?
 
oh

oh its .6 meters right?
 
\lambda = \frac{v}{f}

So...

\lambda= \frac{344}{600}
 
Thanks Very Helpful!
 
Good to hear.
 
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