Finding weight with force and theta

AI Thread Summary
To determine the weight W when a force of 26.0N is directed along the leg, the user initially calculated the vertical component using the angle, resulting in 24.4N. However, this calculation was deemed incorrect, prompting a suggestion to consider the tension in the string sections, which should equal mg. The discussion emphasizes resolving these tensions into x and y components for accurate analysis. It also highlights that the tension remains consistent across all sections of the string due to its continuity. Properly accounting for the tensions in both string segments is crucial for solving the problem accurately.
k2var2002
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Homework Statement


What must W be when the force directed along the leg is 26.0N
http://session.masteringphysics.com/problemAsset/1012378/6/image5.42.jpg

Homework Equations


\SigmaF=ma=mg


The Attempt at a Solution


I used the two angles and drew the y-axis down from the top downward segment to form "two" right triangles. I considered downward on the y-axis to be positive. And finally combined the two angles(70) and took 26sin(70)= 24.4N

Any suggestions would be greatly appreciated.
 
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Your calculation is wrong.
Consider the tension in the two sections of the string be T, which is equal to mg. Resolve these tensions into two components along x and y-axis and proceed.
 
What are the two strings that I should account for with accompanied tension?
 
Since string is contentious, tension in all four sections is the same. Here you have to consider the tension in the section of string between two pulleys.
 

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