Finding work with displacement and weight.

AI Thread Summary
The discussion focuses on calculating the work done lifting a 5.0 kg toolbox 0.5 meters on Earth compared to the Moon. The key formula used is work = force x displacement, with force being the product of mass and gravitational acceleration. On Earth, the work calculated is 24.5 units, while on the Moon, it is significantly less at 4.08 units due to the Moon's gravity being one-sixth that of Earth's. The participant expresses satisfaction with their calculations and appreciation for community support. This highlights the impact of gravitational differences on work done in varying environments.
Bluepie97
Messages
6
Reaction score
2

Homework Statement


Steve lifts a 5.0kg toolbox 0.5 meters off the ground. Compare the amount of work that would be done on Earth to the amount that would be done on the moon.

Homework Equations

The Attempt at a Solution


(no idea what i am doing)

work = force x displacement

x = (5/a) (.5) cos 9.8
 
Physics news on Phys.org
Hint: since the mass of moon is less than that of Earth , therefore its gravity is 1/6th of the gravity at earth.
 
Ok think i fixed it up a bit.
5 x g (planet) = f
w = f x .5
 
w Earth = 24.5 (units)
w moon = 4.08 (units)
 
  • Like
Likes mooncrater
Yup...its correct...!
 
Ok :) thanks for your help. glad to be a part of the community now.
 
  • Like
Likes mooncrater

Thread 'Errors and significant figures'

I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
View full post »
Thread 'A cylinder connected to a hanging mass'

Thread 'A cylinder connected to a hanging mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
View full post »

Similar threads

Does a person burn calories when lowering a weight?
Replies
9
Views
2K
Using virtual work to find the angle of a bar supported by two planes
Replies
22
Views
2K
Resistance force changing the velocity of an object
Replies
8
Views
1K
What is the Work Done During a 100m Sprint?
Replies
16
Views
2K
Work-energy solution for a hanging weight
Replies
5
Views
2K
Lifting an object, kinetic energy, work and forces
Replies
11
Views
5K
Calculating the work done from an equation for variable force
Replies
2
Views
2K
Find work given a pulley and two weights
Replies
6
Views
4K
Find time given a force with respect to displacement
Replies
12
Views
3K
How much work can be done given force, mass, angle & displacement?
Replies
18
Views
4K

Hot Threads

Recent Insights

Back
Top