Finding the xyz Coordinates of Point C in an Isosceles Triangle

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To find the xyz coordinates of point C in an isosceles triangle ABC with given points A and B, it is clarified that the triangle lies on a plane, thus only xy coordinates are needed. The angle at B is specified as m, leading to the other two angles being 90 - m/2. Additionally, point B must be positioned on the perpendicular bisector of line segment AC. This information allows for the derivation of point C's coordinates based on the triangle's geometric properties. Understanding these constraints is essential for implementing the solution in the computer program.
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Finding xyz coords of...

Given: ABC is an isosceles triangle; AB=BC; A(x,y,z); B(x',y',z'); m<ABC=m

I need, based on this information, a way to get the xyz coordinates of C. It's for a computer program I'm writing, and I'm afraid I'm rather unknowlegable about how to solve this type of problem- could someone please give me (an) equation(s) for this? The way those equation(s) work would be appreciated as well, but the equation(s) by themselves are all I really NEED.

Thank you very much.
 
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Unfortunately, given that you have expressed this in 3d space you will not be able to find a unique point which completes your triangle. There will be infinitely many triangles, each laying in a different plane.

I am not sure what your constriction
m<ABC=m

means, could you elaborate on that?
 
Ah yes, such a silly mistake. I assumed I would need xyz coords since the program deals with 3d space, but the triangle is on a plane... I actually only require xy coords.

And by m<ABC=m I meant "measure of angle ABC = m". Since I am unaware of the way to type a proper angle symbol, I used < :P.
 
Well, if angle B has measure m, then the other two angles have measure 90-m/2. Does that help?

(Also, B must lie on the perpendicular bisector of AC)
 
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