Finding zero of function problem

  • Thread starter Thread starter marcuss
  • Start date Start date
  • Tags Tags
    Function Zero
Click For Summary
SUMMARY

The discussion centers on finding the zero of the function f(x) = tan(3^x) within the interval [0, 1.4]. The initial derivative provided was incorrect; the correct derivative is f'(x) = 3^x log(3) sec^2(3^x). Participants clarified the problem and emphasized the importance of correctly interpreting the function and its derivative to find the roots effectively.

PREREQUISITES
  • Understanding of trigonometric functions, specifically the tangent function.
  • Knowledge of derivatives and differentiation rules.
  • Familiarity with exponential functions, particularly the function 3^x.
  • Basic grasp of logarithmic functions, especially log(3).
NEXT STEPS
  • Study the properties of the tangent function and its behavior in different intervals.
  • Learn how to apply the chain rule in differentiation, particularly for composite functions.
  • Explore numerical methods for finding roots of functions, such as the Newton-Raphson method.
  • Investigate the implications of the secant function in calculus and its applications in finding derivatives.
USEFUL FOR

Students studying calculus, particularly those focusing on derivatives and root-finding techniques, as well as educators looking for examples of function analysis and differentiation.

marcuss
Messages
12
Reaction score
0

Homework Statement



the function f(x)=tan(3^x) has one zero in the interval [0,1.4]. The derivative at this point is


The Attempt at a Solution



f'(x)= sec^2(3^x)*x3^(x-1) and i really can't seem to get a zero from that because i really don't know where to start and if I am misinterpreting the problem please tell me that. Thanks
 
Physics news on Phys.org
Wait, what is the initial question?
Are you trying to find roots of:

[tex]y=\tan{(3^x})[/tex]
http://img7.imageshack.us/img7/7748/tan3x.jpg
 
Last edited by a moderator:
If that's the case, your derivative is incorrect.

[tex]f'(x) = 3^x \log(3) \sec^2({3^x})[/tex]
 

Similar threads

Replies
1
Views
2K
  • · Replies 8 ·
Replies
8
Views
1K
  • · Replies 40 ·
2
Replies
40
Views
5K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 21 ·
Replies
21
Views
3K
Replies
2
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
22
Views
3K
  • · Replies 10 ·
Replies
10
Views
3K