Finite-Compliment Topology and intersection of interior

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[SOLVED]Finite-Compliment Topology and intersection of interior

Homework Statement



Given topological space (R^{1}, finite compliment topology), find counter example to show that

Arbitary Intersection of (interior of subset of R^{1}) is not equal to Interior of (arbitary intersection of subset of R^{1}).

\bigcap^{\infty}_{n=1}int(A_{n})\neq int(\bigcap^{\infty}_{n=1}A_{n})

Homework Equations



When we consider topological space (R^{1}, usual topology), it is easy to find out that [-1/n, 1/n] is the example.


The Attempt at a Solution



First, I thought what shapes the open of topological space (R^{1}, finite compliment topology) might have, and it seems to have some shape of real line having finite omissions.
And I tried A_{n} = R-[-1/n, 1/n], and [-1/n, 1/n], but found out all of these are not counterexample..
 
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Look at random subsets of R, and study what their interiors look like.
 
A(n) = R-{n}

A(n)=R-{n} is the counterexample...
I tried this case many times but it was not the counterexample,
but after some fresh air, it is clear this is counter example..
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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