Finite Difference: Developing 2nd Order Fromms Scheme (Help)

Thread starter flyingcarpet
Start date Apr 10, 2008
Tags

Difference Finite Finite difference

Apr 10, 2008

flyingcarpet

how can i develope second order Fromms difference scheme by using these points:
(i-2, i-1, i , i+1) Please help me.

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Apr 10, 2008

tiny-tim

Science Advisor

Homework Helper

Hi flyingcarpet!

What's a Fromms difference scheme?

I can't find Fromm on wikipedia or google …

Thread 'Greatest possible value of a constant in polynomial'

Since ##px^9+q## is the factor, then ##x^9=\frac{-q}{p}## will be one of the roots. Let ##f(x)=27x^{18}+bx^9+70##, then: $$27\left(\frac{-q}{p}\right)^2+b\left(\frac{-q}{p}\right)+70=0$$ $$b=27 \frac{q}{p}+70 \frac{p}{q}$$ $$b=\frac{27q^2+70p^2}{pq}$$ From this expression, it looks like there is no greatest value of ##b## because increasing the value of ##p## and ##q## will also increase the value of ##b##. How to find the greatest value of ##b##? Thanks

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