If you just want the field to exist, certainly. If you want the multiplication on the field to be efficiently computable, probably not. Suppose that G is a group with a hard discrete logarithm. Note that for a discrete log to be well-defined over G, G must be cyclic. The only cyclic groups which can be the additive group of a finite field are those of prime order. Now, if G has prime order p, there are exactly p-1 multiplicative structures on G which will turn it into a field. Each is defined by picking a nonzero element g in G to be the multiplicative identity, and then defining (ag)*(bg) = (ab)g. Notice that computing the multiplication on G is precisely to solve the computational Diffie-Hellman problem for G. Thus, the only to have what you ask for while still keeping the multiplication on G efficiently computable would be to find a group for which discrete logarithms are hard, but Diffie-Hellman is easy. It can be shown that under certain relatively mild number-theoretic assumptions that these two problems are actually equivalent (see Maurer, Ueli M. (1994), Towards the Equivalence of Breaking the Diffie-Hellman Protocol and Computing Discrete Logarithms). So you probably can't get what you want here.