wrobel
Science Advisor
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Oh! Now I see what you call Lie group theory. This is not yet Lie group theory this is just some trivial argument. Lie group theory is a serious mathematical branch. By the way, your formulas are too cumbersome. Particularly there is no need to refer on coordinate representations every time. Everything is much simpler.vanhees71 said:With Lie-group theory that's very easy to understand.
Let ##u## be any vector frozen into a rigid body. The rigid body moves so that ##u=u(t)##. Define a linear operator $$A(t)u(0)=u(t).\qquad (!)$$ It is a unitary operator it's clear:
$$AA^*=I,\qquad (*)$$
Actually, formulas (*) and (!) are the definition of a rigid body.
Differentiate formula (!):
$$\dot u(t)=\dot A(t)u(0)=\dot A(t)A^{-1}(t)u(t)=\dot A(t)A^*(t)u(t).\qquad (**)$$
The operator ##\Omega=\dot AA^*## is skew-symmetric: ##\Omega^*=-\Omega##. Indeed, just take ##\frac{d}{dt}## from both sides of (*).
And finally, any skew-symmetric operator in ##\mathbb{R}^3## can unequally be presented with the help of (pseudo) vector such that ##\Omega x=\omega\times x,## and correspondingly formula (**) takes the form ##\dot u(t)=\omega\times u(t)##
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