Firing a spherical bullet into a watertank

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Discussion Overview

The discussion revolves around the problem of determining how far a spherical bullet will traverse when fired horizontally into a watertank, focusing on the effects of non-constant acceleration due to a retarding force proportional to velocity.

Discussion Character

  • Homework-related, Mathematical reasoning

Main Points Raised

  • One participant presents a model where the retarding force on the bullet is given by F = -k · v, leading to a non-constant acceleration described by a = -k v / m.
  • The same participant expresses uncertainty about integrating the acceleration to find the position function x(t) due to the dependence of acceleration on velocity rather than time.
  • Another participant suggests that the differential equation m · \ddot{x} - k · \dot{x} = 0 can be solved straightforwardly, implying a potential solution exists.
  • There is a mention of the thread being posted in the wrong section, indicating a procedural issue rather than a technical disagreement.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the approach to solving the problem, as one participant expresses uncertainty about the integration process while another claims the differential equation can be solved easily. The discussion remains unresolved regarding the method of solution.

Contextual Notes

There is a lack of clarity on the assumptions regarding the constant k and its dependence on the specific conditions of the watertank and bullet interaction. The integration steps and the implications of the non-constant acceleration are not fully explored.

TheMan112
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I've got a problem, involving non-constant acceleration:

If we fire a spherical bullet horizontally into a watertank, how far will the bullet traverse?

I've figured as much that a spherical bullet provides a retarding force:

F = -k \cdot v where k is a constant.

This should provide the following non-constant acceleration due to Newtons 2nd law.

a = \frac{F}{m} = - {\frac{k v}{m}}

I'm thinking I should integrate two times over a(t) to get an expression for x(t), but since "a" is proportional to v(t) and not directly to t, I don't know how to do it without getting a recursive expression.
 
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The differential equation to solve is:

m \ddot{x} - k \dot{x} = 0

And solutions are fairly straightforward to find.
 
you already posted this in HW-section.
 
Yes, my apologies. I started this thread before I noticed one should ask such questions i the HW-section. I'm going to post my reply to Andy there, you may remove this thread.
 
TheMan112 said:
Yes, my apologies. I started this thread before I noticed one should ask such questions i the HW-section. I'm going to post my reply to Andy there, you may remove this thread.

It's ok, threads are often moved to the correct place after awhile. Just wanted to draw your attention to this :-)
 

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