- #1

Blehs

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The circuit is in the attachment, plus the values that I've managed to find out so far.

Im having problem with figuring out the voltage at t=infinity.

So far i know that when t->infinity that inductors become short circuit. It says to apply current division and then Ohm's Law as a hint, and that's where I am stuffing up.

What i would like to know is - when the switch is closed, does current NOT flow through any of the resistors afterwards? Cause when i try to trace current flow, it ends up flowing through all the resistors anyway.

I tried doing current division; 9//5 = 3.214 ohms

then 3.214 + 8 = 11.214

then 12 x [ 11.214/(6+11.214) ] to determine current through the 6 ohm resistor

multiplying that by 6 gives me 46.904 A

the answer is 43.644 A

Im having problem with figuring out the voltage at t=infinity.

So far i know that when t->infinity that inductors become short circuit. It says to apply current division and then Ohm's Law as a hint, and that's where I am stuffing up.

What i would like to know is - when the switch is closed, does current NOT flow through any of the resistors afterwards? Cause when i try to trace current flow, it ends up flowing through all the resistors anyway.

I tried doing current division; 9//5 = 3.214 ohms

then 3.214 + 8 = 11.214

then 12 x [ 11.214/(6+11.214) ] to determine current through the 6 ohm resistor

multiplying that by 6 gives me 46.904 A

the answer is 43.644 A