- #1
engineer_dave
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Homework Statement
Find the general solution of 2y(x^3+1)dy + 3x^2(1-y^2)dx = 0
Homework Equations
The Attempt at a Solution
So I first grouped the terms with dy or dx
2y/(1-y^2) dy = -3x^2/(x^3 +1) dx
after integrating both sides and solving, I got
ln (1-y^2)= -ln(x^3 +1) + c
and then after simplifying, it becomes 1-y^2= A/(x^3 + 1) and therefore y^2= -A/(x^3+1) + 1.
The answer according to the book was y^2= 1 + A(x^3 +1). How did they get that??
Maybe if i could get rid of the negative sign for ln, it might help...but please if u can help me, it would be appreciated. Thanks.