First Order Differential Equation Problem

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th3plan
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Homework Statement


A 14 lb weight attached to the end of spring stretches it 4 in. Find the equation of motion if the weight is released from rest at a point 3 inches above equilibrium position


Homework Equations


F=kx
mx''+kx=0


The Attempt at a Solution



ok I need some help just finding out what the k constant is. I know I use hooks Law F=kx, and F is mg=kx. Do i consideer equilibrium when nothing is attached to it, and that is y=0? Then what is the x considered in Hooks Law equation mg=kx , is it the distant its stretched from equilibrium position ?


Thanks
 
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First, this is a undamped second order problem.

I would consider equilibrium is when mg=kx.


th3plan said:

Homework Statement


A 14 lb weight attached to the end of spring stretches it 4 in. Find the equation of motion if the weight is released from rest at a point 3 inches above equilibrium position


Homework Equations


F=kx
mx''+kx=0


The Attempt at a Solution



ok I need some help just finding out what the k constant is. I know I use hooks Law F=kx, and F is mg=kx. Do i consideer equilibrium when nothing is attached to it, and that is y=0? Then what is the x considered in Hooks Law equation mg=kx , is it the distant its stretched from equilibrium position ?


Thanks
 
now what do u mean by equillibrium, is that when its unstretched and no wait? or the differecne between unstretrched and stretches in the middle in other words ?
 
when the spring is stretched (downward) to x_0 such that kx_0=mg, it's equillibrium, that's y=0.

th3plan said:
now what do u mean by equillibrium, is that when its unstretched and no wait? or the differecne between unstretrched and stretches in the middle in other words ?