- #1

Linday12

- 54

- 0

## Homework Statement

[tex]\frac{dy}{dx}[/tex] = [tex]\frac{3xy}{3x^2+7y^2}[/tex], y(1)=1

Express it in the form F(x,y)=0

## The Attempt at a Solution

I'm not sure where I'm going wrong. I let v=y/x,

v+x[tex]\frac{dv}{dx}[/tex] = [tex]\frac{3x^2v}{3x^2+7x^2v^2}[/tex]=[tex]\frac{x^2(3v)}{x^2(3+7v^2)}[/tex]= [tex]\frac{3v}{3+7v^2}[/tex]

[tex]\Rightarrow[/tex] x[tex]\frac{dv}{dx}[/tex] = [tex]\frac{-7v^3}{3+7v^2}[/tex]

I think that's right so far, but I'm not entirely sure. Here is where I feel something is going wrong.

[tex]\frac{3+7v^2}{-7v^3}[/tex] [tex]\frac{dv}{1}[/tex] = [tex]\frac{dx}{x}[/tex]

[tex]\frac{3}{14v^2}[/tex]-ln(abs(v))=ln(x)+c

[tex]\frac{3x^2}{14y^2}[/tex]-ln(abs([tex]\frac{y}{x}[/tex]))-ln(x)+c=0

c=3/14 since y(1)=1

And therefore,

F(x,y)= [tex]\frac{3x^2}{14y^2}[/tex]-ln(abs([tex]\frac{y}{x}[/tex]))-ln(abs(x))-[tex]\frac{3}{14}[/tex]=0

The answer isn't right. If someone could help me find where I've gone wrong, it would be very appreciated. Sorry about the scripting. I'm not skilled at it yet, but, hopefully it's easy enough to read. Thank you!