Hi, can someone please help me with the following ODE? I need to find the general solution.(adsbygoogle = window.adsbygoogle || []).push({});

[tex]

y = xy' + \frac{1}{{y'}}

[/tex]

Rearranging I get a quadratic in dy/dx.

[tex]

x\left( {\frac{{dy}}{{dx}}} \right)^2 - y\left( {\frac{{dy}}{{dx}}} \right) + 1 = 0

[/tex]

[tex]

\frac{{dy}}{{dx}} = \frac{{y \pm \sqrt {y^2 - 4x} }}{{2x}}

[/tex]

I don't know what to do from this point nor am I sure if I've started the right way. Any help would be good thanks.

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# Homework Help: First order ODE

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