This is a problem from Cutnell and Johnson Physics I have set up my formula so that eventually I am solving a quadtratic equation, I am unsure if my calculations are correct, any input would be appreciated. THE QUESTION: An airplane is flying with a velocity of 240 m/s at an angle of 30.0° with the horizontal. When the altitude of the plane is 2.4 km, a flare is released from the plane. The flare hits the target on the ground. What is the angle ? WHAT WE KNOW: Vo: 240 m/s y = 2.4 km Theta: 30 degrees Beta : The unknown angle MY CALCULATIONS: Vo Sin 30 = Voy = -120 m/s (because it is in a downward direction, I think) y = Voy(t) + 1/2ay(t^2) -2,400 = -120(t) + 1/2(-9.80)(t^2) In quadratic Form: -4.9t^2 - 120(t) + 2,400 = 0 t = -120 +/- Sqrt (120^2 - 4(-4.9 x 2400))/2 x -4.9 THIS IS WHERE I GET CONFUSED I am unsure if my signs are correct or if I am solving the formula correctly. I will go ahead and show the rest of my calculations but they are incorrect. (or could have been from the beginning) t = 13.04 s Vo cos 30 = Vox = 207 m/s x = Vox(t) = 2699 m Beta = tan^-1 y/x = tan^-1 2,400/2,699 = 41.64 degrees. <----- *this answer is wrong, I am unsure where I made my error(s). Any help is greatly appreciated.