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Fluid mechanics manometer

  • Thread starter ramilla
  • Start date
  • #1
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Homework Statement


a manometer consisting of tube that is 1.25 cm inner diameter . on one side , the manometer leg contains mercury,10cc of an oil(S.G.=1.4)and 3 cc of air as a bubble in oil . the other leg contains only mercury . both legs are open to atmosphere and static . An accident occurs in which 3cc of oil and air bubble are removed from one leg . how much do mercury height levels change?



Homework Equations


Δp=ρgh


The Attempt at a Solution


i calculated the change in pressure due to 3 cc air bubble
∏/4 * 1.25*1.25*l=3
where l = length of airbubble column
l=2.445 cm .....after that cudnt proceed

plz help me how to do it asap
 

Answers and Replies

  • #2
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plzz sm1 reply
 

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