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Fluid mechanics manometer

  1. Aug 31, 2013 #1
    1. The problem statement, all variables and given/known data
    a manometer consisting of tube that is 1.25 cm inner diameter . on one side , the manometer leg contains mercury,10cc of an oil(S.G.=1.4)and 3 cc of air as a bubble in oil . the other leg contains only mercury . both legs are open to atmosphere and static . An accident occurs in which 3cc of oil and air bubble are removed from one leg . how much do mercury height levels change?



    2. Relevant equations
    Δp=ρgh


    3. The attempt at a solution
    i calculated the change in pressure due to 3 cc air bubble
    ∏/4 * 1.25*1.25*l=3
    where l = length of airbubble column
    l=2.445 cm .....after that cudnt proceed

    plz help me how to do it asap
     
  2. jcsd
  3. Sep 4, 2013 #2
    plzz sm1 reply
     
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