stimulisRK
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I'm interested in making a larger-scale French Press (VIDEO, go to :30) It has a mesh-screening filter that keeps the coffee grounds contained when you push down.
I'm theoretically using a large bucket, like those 5gal buckets at Home Depot, with the dimensions shown below. And theoretically this bucket will have a constant diameter all the way down.
Neglecting the weight of the filtering mechanism/screening, the force needed to move the filter-screening down through the water is equal to the drag force of the water acting on the screen.
I'm not sure what to do now when it comes to calculating the drag force acting on filter-screening.
It will be a stainless-steel 5micron mesh, very small. Something similar to this:
FD = ρV2ACD In the drag force equation, V will be the velocity of the screen moving through the water. I'm assuming the A is going to be the total surface area of all the little strands of wire that make up the screen...right?
Am I starting this off right?
I'm theoretically using a large bucket, like those 5gal buckets at Home Depot, with the dimensions shown below. And theoretically this bucket will have a constant diameter all the way down.
Neglecting the weight of the filtering mechanism/screening, the force needed to move the filter-screening down through the water is equal to the drag force of the water acting on the screen.
I'm not sure what to do now when it comes to calculating the drag force acting on filter-screening.
It will be a stainless-steel 5micron mesh, very small. Something similar to this:
FD = ρV2ACD In the drag force equation, V will be the velocity of the screen moving through the water. I'm assuming the A is going to be the total surface area of all the little strands of wire that make up the screen...right?
Am I starting this off right?