Fluid Mechanics, Renoylds Number

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SUMMARY

The discussion focuses on calculating the terminal velocity of a particle with a density of 1100 kg/m³ in water, given a Reynolds number (Re) of 1.0. The Reynolds number is defined as the ratio of inertial forces to viscous forces, expressed as Re = vsρ/μL, where vs is the mean velocity, ρ is the fluid density, μ is the dynamic viscosity, and L is a characteristic length (diameter). To find the terminal velocity, one must apply the relevant equations that relate these variables, particularly under the condition that the particle no longer accelerates.

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  • Familiarity with the equations of motion for particles in fluid.
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A particle falls in water and reaches its terminal velocity. if the density of the particle is 1100kg/m3, what is the velocity and diameter is Re = 1.0


Again guys bit lost with this one, there are so many different equations relating to this i don't know where to start. hopefully some one with a bit more experience can help me.

Thank you in advance.
 
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A particle falls under gravity. What is the condition at terminal velocity, i.e. the particle no longer accelerates?

the Reynolds number is the ratio of inertial forces (vsρ) to viscous forces (μ/L) and consequently it quantifies the relative importance of these two types of forces for given flow conditions.
http://en.wikipedia.org/wiki/Reynolds_number

vs is mean velocity of fluid or velocity of object in fluid.
 

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