Fluid Mechanics: Weight vs Pressure

AI Thread Summary
The discussion revolves around a fluid mechanics problem involving two non-miscible liquids in a tube, where the equilibrium angle of the interface is given. The initial approach of equating weights on both sides was deemed incorrect, as the correct method involves using pressure differentials at the interface. Participants clarified that the bottom of the tube supports part of the weight of each fluid, which affects the equilibrium condition. The correct ratio of densities is crucial for solving the problem accurately. Ultimately, understanding the role of pressure rather than just weight is essential for resolving the issue.
Prannoy Mehta
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Homework Statement



A thin uniform circular tube is kept in a vertical plane. Equal volumes of (The liquids subtend a right angle at the centre) two non miscible liquids whose densities are a and b respectively fill half of the tube as shown. (The diagram depicts a>b) In equilibrium the radius passing through the interface makes an angle of 30 degrees with the vertical. The ratio of densities a/b is equal to.

Homework Equations



The basic equations of fluid mechanics given in any introductory course.

The Attempt at a Solution



I tried equating the weights on both the side as it must be necessary condition for the equilibrium.
Doing so I have obtained the answer as 3. The answer given in the text is 3.732. Where is the flaw in my concept.

Thanks for all the help.
 
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How can a tube be kept in a plane?
Is the tube lying on its side or standing on end?
I think we need to see the diagram.
 
I thought it was not required, sorry for the trouble..

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The flaw in your logic us using the weights. You ought to be using dp/dz=-ρg, and equating the pressures at the interface.

Chet
 
I still did not understand why that concept of weight is wrong, for equilibrium the weight of the liquid with density a, subtending 60 degrees at the centre, should be equal to that, of the a subtending 30 degrees, and the liquid b which is subtending 90 degrees. I do realize there is a flaw in that concept, just wanted to know what is the flaw..

PS: I got the answer using that method. Thank you :)
 
Prannoy Mehta said:
I still did not understand why that concept of weight is wrong, for equilibrium the weight of the liquid with density a, subtending 60 degrees at the centre, should be equal to that, of the a subtending 30 degrees, and the liquid b which is subtending 90 degrees. I do realize there is a flaw in that concept, just wanted to know what is the flaw..
You are aware that the bottom of the curved tube wall supports part of the weight of each fluid, correct?

Chet
 
Yes, I got it now. I din't think of it that perspective.
 
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