Fluid Statistics Homework: Gauge Pressure and Vertical Distance Calculation

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The discussion revolves around calculating gauge pressure and vertical distance in a u-shaped tube containing mercury and water. For part (a), the gauge pressure at the water-mercury interface is calculated using the formula p = p_0 + rho * g * h, resulting in an answer of 1.47 x 10^3 Pa. In part (b), the vertical distance from the mercury's top to the water's top is determined to be 13.9 cm. Participants emphasize the importance of using the correct density of water and suggest drawing a diagram for better understanding. Ultimately, the original poster successfully resolves the problem with guidance from others.
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Homework Statement


A u-shaped tube open to air at both ends contains some mercury. A quantity of water is carefully poured into the left arm of the tube until the vertical height of water is 15 cm.

Homework Equations


(a)What is the gauge pressure at the water-mercury interface?[ans 1.47*10^3Pa]

(b)calculate the vertical distance h from the top of the mercury in the right-hand arm of the tube to the top of the water in the left-arm.[ans 13.9 cm]

The Attempt at a Solution


(a) p=p_0 +rho*g*h
p = 0 + 13.6*10^3 *9.8*0.15
p= 1.99*10^4
(b) 13-1.47=13.5
 
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Nhlaka said:
(a) p=p_0 +rho*g*h
p = 0 + 13.6*10^3 *9.8*0.15
p= 1.99*10^4
Check your value for the density of water.
 
The answers are already given in brackets so my problem is deriving them:confused:
 
Nhlaka said:
The answers are already given in brackets so my problem is deriving them:confused:
You gave an attempted solution and I stated why it was wrong. Did you look up the density of water?
 
Thanks a million really appreaciate:smile:
 
How do i then tickle (b) I am totally clueless on that
 
Nhlaka said:
How do i then tickle (b) I am totally clueless on that
Draw a picture. Hint: At the same vertical position (height), the pressure must be the same. Imagine a horizontal line that intersects the mercury/water boundary.
 
Thank you very much Pf mentor i got the solution to the question:smile::smile:
 

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