Flux density in magnetic circuit

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SUMMARY

The discussion focuses on calculating the flux density in a magnetic circuit with a core permeability (μr) of 1000, a cross-sectional area of 4 cm², a length (L) of 42 cm, an air gap (Ig) of 0.1 cm, 500 turns, and a current (I) of 0.2 A. The formula used is Flux = NI / ((L / (μ0 * μr * A)) + (G / (A * μ0))). The calculated flux density is 0.000035493, although the units remain unclear to the participants. Clarification on unit conversion and the correctness of the calculation is sought.

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  • Understanding of magnetic circuits and flux density
  • Familiarity with the concept of magnetomotive force (MMF)
  • Knowledge of reluctance in magnetic circuits
  • Basic proficiency in unit conversions related to magnetic properties
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Students in electrical engineering, physics enthusiasts, and professionals involved in magnetic circuit design and analysis will benefit from this discussion.

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Homework Statement


Consider the magnetic circuit shown in figure 3
Assuming that the core (μr=1000) has a uniform cross section of 4 cm^2, determine the flux density in the air gap the picture is very small so here are the values L=42cm, Ig=0.1cm, turns=500, and I=0.2A


Homework Equations


Flux=magnetomotive force/reluctance or NI/((L/μ0(μr)A)+(G/Aμ0))


The Attempt at a Solution


When I plug the values given in the problem statements and figure 3. I get .000035493 I am not sure of the units however?
 

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Is the problem not clear?
 
Common guys give me a push or something
 
Hey is this correct guys? Anything?
 

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