Understanding Flux of Vector Fields: Equations, Solutions, and Common Mistakes

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The discussion focuses on understanding the flux of vector fields and the correct application of formulas. A user questions the discrepancy in their results due to a negative sign in their normal vector calculation. It is clarified that the surface representation must be appropriate, as using dependent variables can lead to errors. The correct approach involves parameterizing the surface and ensuring the normal vector has the correct direction. The conversation concludes with the user feeling more confident about their understanding and approach.
yecko
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Homework Statement



Example 2:[/B]
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Homework Equations


Flux=integrate -Pgx-Qgy+R of the proj. area on xy plane for z=g(x,y)

The Attempt at a Solution


Why do my attempt is wrong? The example is using the foundational formula while I use the stock formula from the book, why is there a negative sign difference between the answers? Or is that my formula used inappropiately?

Thanks![/B]
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One reason PF discourages the use of images is that they are difficult to edit. On your first line you have the equation ##g = y = x^2##, whatever that means. You are likely using the formula for a surface of the form ##z = g(x,y)##. The surface ##y = x^2## is not that kind of surface because ##y## and ##x## are not independent. The easiest way to represent the surface is ##y = g(x,z)##. In any case, however you did it, your normal vector is in the wrong direction. The ##y## component of your normal vector must be negative.
 
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LCKurtz said:
The y coordinate of your normal vector must be negative.
Thanks for pointing out the problem...
yecko said:
Flux=integrate -Pgx-Qgy+R of the proj. area on xy plane for z=g(x,y)
but how can we see the direction of normal vector in this formula?
and how to correct it? (simply by adding a negative sign?)
 
yecko said:
Thanks for pointing out the problem...

but how can we see the direction of normal vector in this formula?
and how to correct it? (simply by adding a negative sign?)

I can't tell how you got your normal or what formula you used because you didn't show your work. What I would do is parameterize the surface like this$$
\vec R(x,z) = \langle x, x^2, z\rangle$$and get a normal by ##\vec R_x\times \vec R_z## and take it or its opposite, whichever has a negative ##y## component.
 
Alright! I believe I've got it! thanks!
 

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Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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