Focal length of combined glass lens and water lens

AI Thread Summary
The discussion revolves around the application of the lens maker formula for a combined glass and water lens system. A participant initially struggles with the formula, calculating a focal length of -160 cm, but later realizes that the setup includes a glass lens with air on one side and water on the other, along with a concave water lens. The key point is that the solution manual introduces a thin air layer between the lenses, allowing the refractive index to be set to 1 for both lenses. This clarification helps resolve the confusion regarding the calculations. Understanding the configuration of the lenses is crucial for accurate focal length determination.
desmond iking
Messages
284
Reaction score
2

Homework Statement



please refer to the photo,

Homework Equations





The Attempt at a Solution


why can't I directly use the lens maker formula to get the ans ?
my working is 1/f = ( (1.5-1.33) /1.33) x ( (1/20) + 0 ) ...finally , i get my f = -160cm.
the radius of curvature of glass is 0
 

Attachments

  • IMG_20140818_205126[1].jpg
    IMG_20140818_205126[1].jpg
    30.5 KB · Views: 571
  • IMG_20140818_205250[1].jpg
    IMG_20140818_205250[1].jpg
    23.7 KB · Views: 551
Physics news on Phys.org
Strange, I get +160 cm using the lens maker formula as you write it.
That would be for a glass lens fully submerged in water (the 1.33 for n0)

But the exercise has a glass lens with air on one side and water on the other PLUS a water lens (concave!) with glass on one side and air on the other. In other words, a combination of TWO lenses.

The solution manual deviously inserts a thin layer of air between the lenses so that the n0 can be set to 1 for both lenses.
 
  • Like
Likes Umrao and desmond iking
understand it now finally!
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanged mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top