- #1

MMCS

- 151

- 0

Find the coordinates of the foot of the perpendicular from the point A with coordinates (-5,5) to the line 10x+2y-3= 0

1.) gradient of original line -10/2, gradient of intercepting line 1/5

2.) equation of intercepting line y-5 = 1/5(x+1) *5

3.)5y-25 = x+1 re-arranging gives 5y-x = 26

4.) solve simultaneously -10x-50y=-260 ( *-10 )

10x+2y=3

-48y=-257

y=5.354

Substituting y into either equation

x= -0.7708

From the program i know these answers arnt correct

Any pointers would be appreciated,

Thanks