Force and Motionfinding tension?

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The discussion revolves around calculating the tension in a cable pulling an elevator cab weighing 2000 kg, with a person inside. When a coin is dropped, it accelerates at 8.00 m/s², prompting the need to find the tension in the cable. The user has created a free-body diagram and identified the forces acting on the system, including gravitational force and normal force. Key equations are provided, indicating that the sum of forces in the vertical direction must equal the net force, leading to the equation T = m(a + g). The user seeks clarification on the concept of tension, mistakenly considering it as time, and is encouraged to plug in known values to solve for T.
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Homework Statement


"Elevator cab is pulled upward by a cable. the cab and its one person inside weigh 2000kg.when that person drops a coin, its acceleration to the cab is 8.00m/s^2.
what is the tension in the cable?

I feel as tho i know what to do but the "tension" is throwing me off. I've never been asked to find it before. is there any other ways this might be worded for understanding?



Homework Equations


m=2000kg
Fx=MAx
Fy=MAy




The Attempt at a Solution


I am unsure how to add drawing in here. but basicly i made a free-body-diagram.
with Fg(gravity) and a arrow pointing downwards. Fg=mg >> Fg=(2000)(9.81)= 19620
and with F or "N" for normal pointing upwards ^.

I am not looking for anyone to do this. just some hints and ideas as how to start :(
thank you
 
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you need to sum the forces; the sum of those forces must equal the net Force

Sum of the Forces in Y = T - mg = ma; where a is the acceleration of the whole system
 
fizzynoob said:
Sum of the Forces in Y = T - mg = ma; where a is the acceleration of the whole system
Fy= T -mg = ma
Fy= T = ma + mg
Fy= T = m(a+g)

T=time?
m=mass 2000kg
a=8.00m/s^2
g=-9.8a

correct?
 
T does not equal time, it is tension. Maybe i should of put Ft.

So you solved for T right, now you your acceleration and you know gravity. Plug in values
 
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