Force attracting a particle and time required

LazyMan
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Homework Statement


A particle of mass m is released from rest a distance b from a fixed origin of force that attracts the particle according to the inverse square law:
F(x) = -kx-2

Show that the time required for the particle to reach the origin is
Pi times (mb3/8k)1/2


Homework Equations


I have no idea what you need


The Attempt at a Solution


I am sad to say I have no clue how to even star this one. Any help would be nice, just don't give me the answer just yet.
 
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Use energy mechanical energy conservation and solve for dx/dt. After you do that you might see what comes next.
 
Hi, I had an exam and I completely messed up a problem. Especially one part which was necessary for the rest of the problem. Basically, I have a wormhole metric: $$(ds)^2 = -(dt)^2 + (dr)^2 + (r^2 + b^2)( (d\theta)^2 + sin^2 \theta (d\phi)^2 )$$ Where ##b=1## with an orbit only in the equatorial plane. We also know from the question that the orbit must satisfy this relationship: $$\varepsilon = \frac{1}{2} (\frac{dr}{d\tau})^2 + V_{eff}(r)$$ Ultimately, I was tasked to find the initial...
The value of H equals ## 10^{3}## in natural units, According to : https://en.wikipedia.org/wiki/Natural_units, ## t \sim 10^{-21} sec = 10^{21} Hz ##, and since ## \text{GeV} \sim 10^{24} \text{Hz } ##, ## GeV \sim 10^{24} \times 10^{-21} = 10^3 ## in natural units. So is this conversion correct? Also in the above formula, can I convert H to that natural units , since it’s a constant, while keeping k in Hz ?
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