Force equilibrium of a thick-walled pipe

AI Thread Summary
The discussion centers on calculating the forces acting on screws securing a thick-walled pipe under an applied moment. The initial formula proposed for the force on each screw is F = M/(N*b), based on moment equilibrium. Clarification is sought regarding whether this force represents shear force and if material deformation should be considered in the equilibrium calculation. It is noted that if friction is negligible, moment equilibrium might suffice for determining the shear force. Finally, the shear force, along with the preload on the bolts, can be used to assess the number of screws needed to prevent yielding of the screw material.
Arcturus82
Messages
4
Reaction score
0
Dear all,

I have a thick-walled pipe with an inner radius a and an outer radius b. The pipe is mounted to an outer rigid surrounding by N number of screws (applied at radius b) equally distributed around the pipe. Given an applied moment M on the inner radius a, I want to calculate the forces acting on the screws in order to verify that the screws are strong enough to keep the pipe in place.

Would the force F on each screw in such situation simply be F = M/(N*b) ? That is by using momentum equilibirum M = N*b*F around the center of the pipe. Or would the material deformation change this equilibrium in any way?

I would appreciate any help you may offer.

All the best
 
Physics news on Phys.org
"F on each screw"...in which direction? I presume that the F that appears in F=M/(N*b) is the F tangential to the outside of the pipe and right where the bolt contacts the pipe...in other words, this is friction force (if negligible deformation); it would be the same force that is trying to "bend" the bolt, but it is different from the force along the axis of the bolt...am I correct? Where, of course, Ffirction = Faxial-bolt X Friction-Coeff. ?
 
Thank you very much for your reply.

I realize that I was quite unclear in my question. There is going to be bolted joints between the rigid surrounding and the pipe, where the screw threads are in the pipe. So with the force F, I was referring to the shear force that would act on one screw. In the case where any friction at the interface between the pipe and the surrounding can be neglected, I wondered if moment equilibrium would be the only factor I have to consider? Because that would simply give me F = M/(N*b). However, I am unsure if I need to account for the deformation of the pipe since the moment is acting on the inner surface.

If I know the shear force together with the preload along the bolt axis, I can then go ahead and use for example von Mises yield criterion to determine how many screws of a specific type that are needed to hold the pipe in place without reaching the yield point of the screw material.
 
Last edited:
Thread 'Question about pressure of a liquid'
I am looking at pressure in liquids and I am testing my idea. The vertical tube is 100m, the contraption is filled with water. The vertical tube is very thin(maybe 1mm^2 cross section). The area of the base is ~100m^2. Will he top half be launched in the air if suddenly it cracked?- assuming its light enough. I want to test my idea that if I had a thin long ruber tube that I lifted up, then the pressure at "red lines" will be high and that the $force = pressure * area$ would be massive...
I feel it should be solvable we just need to find a perfect pattern, and there will be a general pattern since the forces acting are based on a single function, so..... you can't actually say it is unsolvable right? Cause imaging 3 bodies actually existed somwhere in this universe then nature isn't gonna wait till we predict it! And yea I have checked in many places that tiny changes cause large changes so it becomes chaos........ but still I just can't accept that it is impossible to solve...
Back
Top