Force Exerted by Floor on 70kg Person in Elevator

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To determine the force exerted by the floor on a 70kg person in an elevator accelerating downwards at -3 m/s², one must apply Newton's second law. The gravitational force acting on the person is calculated as weight (mg), which equals 686 N (70kg * 9.8 m/s²). The net force can be determined by subtracting the elevator's downward acceleration from the gravitational force, resulting in a force exerted by the floor of 556 N. Participants emphasize the importance of showing work to facilitate assistance in solving the problem. Understanding the forces at play is crucial for arriving at the correct answer.
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Suppose a 70kg person is in an elevator. The acceleration of the elevator is -3m/s/s. What force would the floor exert on the person? Please show work...
 
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contlee said:
Suppose a 70kg person is in an elevator. The acceleration of the elevator is -3m/s/s. What force would the floor exert on the person? Please show work...
Contlee, welcome to PF! Please read the rules of this forum...it is you who must show the work. Examine all the forces acting on the person and use Newton's laws. If you show your attempt, someone will assist you in your arriving at the correct answer.
 
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