Force needed to keep object from accelerating problem

AI Thread Summary
The discussion revolves around calculating the force needed to prevent a 280kg box from accelerating down a 30-degree incline, factoring in kinetic friction with a coefficient of 0.4. The original poster struggled with their calculations, particularly in determining the forces acting on the box, including gravitational force components, friction, and the force exerted by a man pushing against the box. They were advised to draw a free body diagram (FBD) to visualize the forces and to sum them in both the x and y directions for clarity. Ultimately, the poster realized their error was related to miscalculating an angle, which resolved their confusion. This highlights the importance of accurately analyzing forces in physics problems.
joej
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This problem is keeping me up all night, I did what I thought was right to figure out the force needed but the answer sheet tells me that my solution is wrong, spend 4 hours trying to figure out what I did wrong can't come up with anything:

A 280kg box slides 4.3m down a 30 degree incline and is kept from accelerating by a man who is pushing back on it parallel to the incline. The effective coefficient of kinetic friction is 0.4. Calculate the force exerted by the man.

It might well be that I am completely out of my mind today and forgetting some basic thing that I am supposed to do, anyways I tried to do:

Ff = 280 * 9.8 * sin30 * 0.4

I am quite sure actually that I am forgetting something... just god damn don't know what it is.

thnx for any help in advance.
 
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Try \sum F=0

Now, as for the forces you seem to be missing one. Draw a FBD. Put ALL forces acting on the box. Sum them in the x and y directions. If you need help determining the forces post what you've got thus far and we'll see if we can figure out which force(s) is/are missing.

Good luck

PS welcome.
 
hrm well the FBD that I drew I set up the x-axis to be parallel to the incline and basically I have the following forces:

g, pulling the object down (is split into two forces since it is @ an incline the force pulling the box down the incline should be sin30 of the full force, I believe)
coefficiant of friction force (0.4) going against g
force that the person excerts on the box also going against g
and normal force which I believe should be equal to cos60 of the g force
 
So you have:

\sum F_x=W_x-F_{fr}-F_{man}=0

You know how to find the component of the weight vector in the x direction. That Wieght of the box is pulling the box to the right (positive). The man and friction are pushing to the left (negative).

How do you determine the force of friction? Once you figure this out you'll have all the parts needed to solve this question.
 
that is where I get lost I mean okay I determine the force of friction which should be equal to:
coefficient of friction * netForce

now net force will be mass * acceleration (all in x-axis)

this I can do with: mass * acceleration * sin30

and so here I get lost as to what I should do next



----edit----

never mind I got it, seems I was messing up one cos angle and that was causing all the problems duh god I'm stupid :-p
 
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