Force of a Bullet Impact: F=mv?

In summary: No=1&productNo=45ACP&caliber=Auto&style=Gold+Dot%2C+45In summary, the bullet has a muzzle velocity of 890ft/s and a weight of 230gr. It has an acceleration of 9.8m/s2 and a force of 6,760N.
  • #1
Kevlarji
6
0
Hi,

I'm modelling a bullet impacting with a wall, I wish to know how much force the bullet hits the wall with.

Will it simply be a case of F=mv ?
 
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  • #2
Force is rate of change of momentum.
i.e the change in momentum/time taken
If you have some idea how long it takes the bullet to come to rest you should be able to get an answer or at least an estimate.
 
  • #3
The easiest quantity to estimate is the impulse, which is just the change in momentum of the bullet. For this, all you would need to know is the initial and final velocities of the bullet, and the mass of the bullet. Obviously this quantity will vary.

From the impulse, if you know the time it takes to make the bullet change velocities, you can get the average force of this bullet via F=I/t.

Probably more important than the force would be the pressure which is simply P=F/A, where A is the area of the bullet head. This will give you an idea of the penetrating power of bullets.
 
  • #4
I believe you could look at this inversely. A bullet works by projecting a particle with certain speed through combustion. When this combustion occurs, a large pressure it built up within the chamber of the barrel behind the bullet. This pressure will then seek to equalize, projecting the bullet forward. This pressure's ability to project the bullet is proportional to the volume of the barrel. A certain amount of pressure will displace a certain amount of air. The barrel of a hand gun is usually smaller then this amount, and only a fractional portion of the pressure is used for projection. Once the bullet is outside the barrel, the pressure will dissipate in the atmosphere. We can then assume that maximum velocity is reached at the tip of the barrel. Once beyond the barrel, external factors begin to slow it. Therefore, the barrel length must be considered.
Luckily, this is understood by the ammo companies. Their products almost always list the bullet weight (in grains), velocity (in ft/s), and the test barrel's length for that particular round (in inches). Using the information above, kinematic equations, Newton's laws, and bullet specifications we can find the force of a particular bullet upon leaving the barrel of a gun.
Looking at Speer's 45 Auto Gold Dot specs, we have a test barrel length of 5in, bullet weight of 230gr, and muzzle velocity of 890ft/s.
First we use kinematics to find the bullets acceleration. We are given the initial velocity (0m/s), final velocity [890ft/s (271.27m/s)], and distance [5in (.127m)], and we need to find acceleration. Find and use the appropriate equation.
We now have both acceleration and mass [230gr (.015kg)]. This enables us to use Newton's second law to find the force.
The force at different distances can also be found using the same process and the other specs. I have attached the full specs in case you want find these other forces.

http://www.speer-ammo.com/ballistics/detail.aspx?loadNo=23966
 
  • #5


I would like to clarify that the equation F=mv is the basic formula for calculating the force of an object's impact, where m represents the mass of the object and v represents its velocity. However, in the case of a bullet impacting a wall, there are other factors that need to be considered such as the type of bullet, the material and thickness of the wall, and the angle at which the bullet hits the wall. These factors can greatly affect the force of impact.

To accurately determine the force of a bullet impact, a more detailed analysis and calculations using the laws of motion and principles of energy conservation would be necessary. This would involve taking into account the velocity and mass of the bullet, as well as the conservation of momentum and energy in the collision between the bullet and the wall.

Additionally, it is important to note that the force of impact is not solely determined by the bullet itself, but also by the reaction force of the wall. The force exerted by the wall on the bullet can also affect the overall force of impact.

In conclusion, while the equation F=mv can provide a general understanding of the force of a bullet impact, a more thorough analysis and calculations are needed to accurately determine the force in a specific scenario.
 

1. What is the formula for calculating the force of a bullet impact?

The formula for calculating the force of a bullet impact is F=mv, where F is the force, m is the mass of the bullet, and v is the velocity of the bullet.

2. How does the mass of the bullet affect the force of impact?

The mass of the bullet directly affects the force of impact, as shown in the formula F=mv. A heavier bullet will have a greater force of impact compared to a lighter bullet when fired at the same velocity.

3. Does the velocity of the bullet play a role in the force of impact?

Yes, the velocity of the bullet is a key factor in determining the force of impact. The higher the velocity, the greater the force of impact, as shown in the formula F=mv.

4. What other factors besides mass and velocity can affect the force of a bullet impact?

Other factors that can affect the force of a bullet impact include the type of ammunition used, the distance between the shooter and the target, and the angle at which the bullet strikes the target.

5. Is the force of a bullet impact always lethal?

The force of a bullet impact can vary depending on the factors mentioned above, and not all impacts are lethal. However, a bullet fired at high velocity and with a large mass can cause significant damage and potentially be lethal.

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