A bullet has been shot from a moving car

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SUMMARY

The discussion centers on a physics problem involving a bullet shot from a moving car. The car travels at a speed of 20 m/s, while the bullet is shot forward at 150 m/s. To determine the rise in temperature of the bullet upon hitting a wall, the kinetic energy formula (K.E = 1/2 mv²) and the heat transfer equation (Q = mSΔθ) are utilized. The key conclusion is that the bullet's velocity relative to the wall is the sum of the car's speed and the bullet's speed, which is essential for calculating the kinetic energy and subsequent temperature rise.

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  • Familiarity with heat transfer concepts, including specific heat capacity.
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  • Knowledge of vector addition in physics to analyze relative motion.
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  • Learn about the specific heat capacity and its role in thermal energy calculations.
  • Explore vector addition in physics to better understand relative motion problems.
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Akash47
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Homework Statement


A man in a car moving with a speed ##20~ms^{-1}## shoots a bullet forward with a speed of ##150~ms^{-1}##. The bullet hits a wall and stops. Find the rise in the temperature of the bullet if its specific heat is ##500~Jkg^{-1}K^{-1}##.

Homework Equations


##K.E=1/2~mv^2## and the amount of heat ##Q=mSΔθ##

The Attempt at a Solution


If the real velocity of the bullet can be fined,then the problem will become very easy.I think, as the bullet was moving with the same velocity,so the velocity of the bullet with respect to the wall will be the addition of the velocity of the car and the velocity of the bullet with respect to the car.I want to know whether I am right or not.
 
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Akash47 said:
the velocity of the bullet with respect to the wall will be the addition of the velocity of the car and the velocity of the bullet with respect to the car
Is right
 

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