Force of friction between wheel and axle

In summary: I can't seem to find. Is there a specific equation for this resistance that I'm not looking in the right places?In summary, Jeff was looking for an equation to calculate the friction force that opposes the wheel's rotation. He was not able to find the equation and was hoping someone might be able to help him.
  • #1
gunhed508
10
1
I've been working on a simulation of a Lorenz Waterwheel, and friction was killing it - I couldn't use realistic coefficients of friction. The problem, I discovered was that I was not using the correct equation to calculate the force of friction that counters the wheel's rotation. Having misplaced my physics reference book, I thought I could easily find this equation on the web - not so! After devoting hours of internet search, I cannot for the life of me find this simple equation! Can anyone help me? To clarify what I need, I've provided a basic model below:

View attachment wheel_and_axle_friction.bmp

A wheel of radius rw is centered on an axle of radius ra.
The wheel has mass, m.
There exists a coefficient of static friction between the wheel and axle, us.

What is the equation to calculate the force of friction that opposes rotation of the wheel?

Many thanks!
 
Physics news on Phys.org
  • #2
gunhed508 said:
I've been working on a simulation of a Lorenz Waterwheel, and friction was killing it - I couldn't use realistic coefficients of friction. The problem, I discovered was that I was not using the correct equation to calculate the force of friction that counters the wheel's rotation. Having misplaced my physics reference book, I thought I could easily find this equation on the web - not so! After devoting hours of internet search, I cannot for the life of me find this simple equation! Can anyone help me? To clarify what I need, I've provided a basic model below:

View attachment 21367

A wheel of radius rw is centered on an axle of radius ra.
The wheel has mass, m.
There exists a coefficient of static friction between the wheel and axle, us.

What is the equation to calculate the force of friction that opposes rotation of the wheel?

Many thanks!

Welcome to the PF. The basic equation for frictional force is F = mu * N, where mu is the friction coefficient, and N is the normal force. For the case of the wheel on the axle, you will need to figure out the distribution of the normal force as a function of the angle. Max force on top and tapering off as you get to the sides of the axle.

That force distribution then becomes a torque distribution, which is what resists the rotating motion of the wheel.
 
  • #3
The torque produced by friction in the axle remains the same regardless of the radius of the wheel, however, the force required to produce the torque at the edge of the wheel is rw x tangental force, so the tangental force is decreased if the wheel to axle radius ratio is increased.
 
Last edited:
  • #4
BTW, the use of bearings will reduce the friction force a lot -- can you use bearings in your design?
 
  • #5
berkeman:
Thank you for the welcome on board! Yes, the basic "sliding" friction equation is the one I had incorrectly applied to my model. I have an old Statics textbook from college that I had many years ago, and I remember specifically it had an already laid-out equation for my particular model. (By the way, this is for a computer simulation, so using bearings is simply a matter of using the correct coefficients of static and kinetic friction.) What I'm needing is the equivalent equation of the sliding surfaces physical model for a wheel and axle physical model. I need this to properly sum the forces in each iteration of the simulation.

Jeff:
I had hoped that this was a commonly-needed equation and that it would have been posted somewhere, but I'm beginning to wonder... I'm not wanting to “re-invent the wheel” (no pun intended) by struggling through the calculus required to re-create that equation (I've long forgotten how). I'm hoping someone here will just recall the equation or dig it out from a textbook or reference of some kind. I do recall that the equation included the radius of the axe and the radius of either the outside of the wheel or the inside of the wheel immediately surrounding the axle, which is probably more correct.

Any ideas?
 
  • #6
Make that:

Torque anywhere on the wheel is rw x tangental force at the edge of the wheel, so the larger the radius of the wheel, the less tangental force it takes to produce the same torque.
 
  • #7
Jeff Reid said:
Make that:

Torque anywhere on the wheel is rw x tangental force at the edge of the wheel, so the larger the radius of the wheel, the less tangental force it takes to produce the same torque.

I understand about torque - the net torque on the wheel is only one of the forces on the wheel's angular motion in the simulation. Another force acting on the wheel is the resistance of friction as the wheel grinds around the central axle. It's this resistance I need to calculate, the axle friction.
 
  • #8
gunhed508 said:
I understand about torque - the net torque on the wheel is only one of the forces on the wheel's angular motion in the simulation. Another force acting on the wheel is the resistance of friction as the wheel grinds around the central axle. It's this resistance I need to calculate, the axle friction.

That's a frictional torque. Communication problem?
 
  • #9
berkeman said:
That's a frictional torque. Communication problem?

Frictional torque may be the more correct term, assuming it describes the friction between the wheel and its axle (not to be confused with, say inertia). At the very least, it will give me more keywords to search on the web. Thank you. :)
 
  • #10
Please allow me to re-state the problem.

I had searched the web again, this time for frictional torque, but I still couldn't find what I needed. Most of the examples I saw were experiments where the outcomes of the system's motion had already been measured, and the frictional torque was determined from the data points, quite the opposite of whet I'm doing. What I have is a system where I know all its attributes (mass, size, position, etc.), but I need to calculate how it will end up moving as time progresses. Below is hopefully a more clear explanation of my problem:

Please review the following physical model:
FrictionalTorqueModel.gif


Knowns:
F = tangential force exerted on wheel
m = total mass of wheel
G = acceleration of gravity
ra = radius of axle
ro = outer radius of wheel
ri = inner radius of wheel
μk = coefficient of kinetic friction
Tw = applied torque resulting from F

Unknown (solve for this):
Tf = opposing torque due to friction

Assumptions:
- the wheel is already in motion (i.e. kinetic friction)

I need an equation expressing Tf in terms of the known variables in the system. It's quite possible I'm forgetting something there, such as inertia; it's been way too long since physics class for me to remember! Can anyone help?
 
  • #11
http://www.manchesteruniversitypress.co.uk/uploads/docs/310101.pdf"
 
Last edited by a moderator:
  • #12
Hope it helps.
 
  • #13
eddybob123 said:
http://www.manchesteruniversitypress.co.uk/uploads/docs/310101.pdf"

eddybob123 said:
Hope it helps.

Well, the thread is 2 years old, but that reference is pretty good, so I'll leave your necroposts for now. :smile:
 
Last edited by a moderator:
  • #14
Thank you for giving this thread back some life! :) I still do have an interest in it.

FYI - I took a hard look at a copy of my Statics book a while back and put together this possible solution (see the attached PDF for review). I didn't have room to show all my calculations, but the basic answer is this:

Tw = Tf ≈ rμkmG

I will take a good look at the PDF posted by Berkeman and re-check my work. Any one else who is interested, feel free to check mine. This is a long-term project for a Lorenzean Waterwheel simulation as an "amateur scientist."
 

Attachments

  • Frictional Torque Physical Model - Waterwheel rev 2.pdf
    71.9 KB · Views: 1,184
  • #15
gunhed508 said:
I will take a good look at the PDF posted by Berkeman and re-check my work.

(Actually, the new PDF was posted by eddybob123, and I only quoted it in my response.)
 

What is the force of friction between a wheel and axle?

The force of friction between a wheel and axle is the resistance that occurs when the wheel and axle are in contact with each other and one is in motion. This force is caused by the interaction between the surfaces of the wheel and axle.

How is the force of friction between a wheel and axle calculated?

The force of friction between a wheel and axle can be calculated using the formula F = μN, where F is the force of friction, μ is the coefficient of friction, and N is the normal force between the two surfaces. The coefficient of friction is a measure of how easily the two surfaces slide against each other.

What factors affect the force of friction between a wheel and axle?

The force of friction between a wheel and axle can be affected by several factors, including the type of material used for the wheel and axle, the weight of the load being carried, the speed at which the wheel is rotating, and the surface texture of the wheel and axle.

How can the force of friction between a wheel and axle be reduced?

The force of friction between a wheel and axle can be reduced by using materials with lower coefficients of friction, such as lubricants or materials with smoother surfaces. Additionally, reducing the weight of the load being carried and decreasing the speed at which the wheel is rotating can also help to reduce friction.

What are some real-world applications of the force of friction between a wheel and axle?

The force of friction between a wheel and axle is an important concept in many industries and everyday activities. It is essential for the proper functioning of vehicles, such as cars and bicycles, and is also used in machinery and equipment, such as conveyor belts and pulley systems. Additionally, understanding the force of friction between a wheel and axle can help in designing more efficient and durable products.

Similar threads

Replies
4
Views
1K
  • Mechanics
Replies
10
Views
1K
Replies
22
Views
2K
Replies
29
Views
5K
Replies
8
Views
3K
  • Mechanics
Replies
13
Views
4K
  • Mechanics
Replies
26
Views
490
  • Mechanics
Replies
20
Views
928
Replies
21
Views
2K
Replies
15
Views
1K
Back
Top