Force on an Accelerating Car: Calculating the Net Force

AI Thread Summary
The discussion focuses on calculating the net force exerted on a car with a mass of 710 kg that accelerates from rest to travel 40.0 m in 3.0 seconds. The user correctly calculates the acceleration using the formula d = v0t + 0.5at², resulting in an acceleration of approximately 8.9 m/s². They then apply Newton's second law, F = m•a, to find the net force, which is calculated to be 6319 N. A response suggests adhering to a specific posting template in future discussions, although the original poster provided all necessary information. The calculations and final answer for the net force are deemed correct.
Wanting to Learn
Hello, since this is a new topic in class I just want to check that I am doing the question correctly.
Given:
car mass = 710kg
starts from rest
v0 = 0
travels 40.0m in 3.0s
d = 40.0m
t = 3.0s

Question:
What is the net force exerted on the car?
F = ___N

Work:
First I calculated acceleration:
d = v0t + 0.5at2
40 = 0 + 0.5a32
40 = 4.5a
a = 8.888 => 8.9

Then force:
F = m•a
F = 710•8.9
Answer:
F = 6319N

Is this correct? Thank you in advance.
 
Physics news on Phys.org
Looks OK, but please follow the template next time you post.
 
Thank you. I included all the information which the template asks for; I just found it easier to to format as I did.
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanged mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top