Force on Current-Carrying Conductor

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To find the radius of a proton moving in a magnetic field, the relevant equation is F = Bqv, where F is the magnetic force, B is the magnetic field strength, q is the charge, and v is the velocity. The magnetic force acts as the centripetal force, allowing for the calculation of the radius by equating the two forces. The discussion highlights a common misunderstanding regarding the complexity of the problem, with participants clarifying the straightforward application of the formula. The solution involves recognizing that the magnetic force points toward the center of the circular path. This approach simplifies the process of determining the radius of the proton's circular motion.
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Homework Statement



A proton (q = 1.6 x 10-19C; m = 1.7 x 10-27 kg) is in a uniform 0.25 T magnetic field. The proton moves in a clockwise circle with a tangential speed of 2.8 x 105 m/s.

What is the radius of the circle?

Homework Equations



Not sure what equation to use.

The Attempt at a Solution



We had been learning about magnitude of a magnetic field, and the equation we were working with was B=Fmagnetic/qV, I wasn't sure how to use this to find radius.
 
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Hi cocololo. Yes you can use the equation F=Bqv, which is the force due to the magnetic field which always points towards the centre of the circle so you can equate the magnetic force to the centripetal force and you should be able to workout the radius from that.
 
Oh, of course! I think I was thinking way too hard about this looking for something way more complicated than it actually was. Thanks!
 
You're welcome. Anything else you need help with?
 

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