How Much Force Is Needed to Compress Air in a Sealed Tube?

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To calculate the force needed to compress air in a sealed tube, the ideal gas law (PV=nRT) is essential. The initial volume of air is 1005 cubic feet, and the final volume after compression is 904 cubic feet. The pressure change from 1 atm must be considered, as compressing the air increases its pressure. The force can be determined by calculating the pressure difference and multiplying it by the cross-sectional area of the tube. Understanding these principles will aid in deriving the required force for the compression.
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I have a tube 40' long by 8" internal diameter, sealed at one end.

Assuming an ideal plunger is inserted into the open end, how much force would be required to compress the air (starting at 1 atm) from 40' (1005 ft/cu) to 36' (904 ft/cu)?

Any hints as to the calculation required for this would be appreciated.
Thank you.
 
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Negativ3 said:
I have a tube 40' long by 8" internal diameter, sealed at one end.

Assuming an ideal plunger is inserted into the open end, how much force would be required to compress the air (starting at 1 atm) from 40' (1005 ft/cu) to 36' (904 ft/cu)?

Any hints as to the calculation required for this would be appreciated.
Thank you.
Are you familiar with the ideal gas law?
 

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