Force that will be created on the component

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A 22 kg mass dropped from a height of 180 mm impacts a component with a final velocity of 3.53 m/s. The force exerted on the component can be calculated using the formula F = ma, where 'a' is the acceleration during impact. The discussion highlights that the force exerted by the mass is equal in magnitude and opposite in direction to the force exerted by the component, in accordance with Newton's third law. The duration of the force is not specified, but it is implied that understanding the impact time is crucial for accurate force calculation. Overall, the thread emphasizes the relationship between force, mass, and the effects of impact on components.
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a mass of 22 kg is dropped vertically from 180mm on a component. I know the final velocity while the hit takes place is 3.53m/sqsec. What is
the force that will be created on the component and to what duration the force lasts.
 
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How much force does the mass exert on the componant? Wouldn't the force the componant exerted be equal and opposite, because its pushing back on the mass, to the magnitude of the force the componant exerts? As far as calculating the time I don't know.
 

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