Force to push mass down inclined plane

In summary, in order to keep a 40 kg mass sliding down a frictionless ramp at a constant velocity, a force of mgcos(30) or (40 kg)(9.8 m/s/s)(.866) must be applied in the opposite direction of the component of gravity down the ramp. This can be found by first calculating the normal force and then the friction force using a diagram of the forces on a block on a ramp.
  • #1
ChessFanatic
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Homework Statement



The angle of the ramp is 30 degrees. The mass is 40 kg. What force must be applied to keep the mass sliding down the ramp at constant velocity. The ramp is frictionless*

Homework Equations


I have missed the past few lessons in class, so I'm not sure. I do have a bunch of equations, but I have little clue on how to use them for this problem

The Attempt at a Solution

 
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  • #2
Assuming there is no friction, the force required to cause the mass to move at a constant rate is equal to the component of the mass's weight down the 30-degree incline. When this happens, the total net force on the mass is zero as the accelerative force (gravity) is canceled out, and it moves at a constant rate. The component of weight down the ramp is given by the expression mgcos(30). This, the force required is mgcos(30), or (40 kg)(9.8 m/s/s)(.866). It will be directed in the direction opposite the component of gravity down the ramp.
 
  • #3
You might begin with a review of the forces on a block on a ramp.
You will need to find the normal force pushing the block against the ramp in order to calculate the friction force. Nice diagram here:
http://en.wikiversity.org/wiki/Motion_in_two_dimensions
 
  • #4
I got it, thanks guys
 
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  • #5


To calculate the force required to keep the mass sliding down the ramp at a constant velocity, we can use the equation F = mgsinθ, where F is the force, m is the mass, g is the acceleration due to gravity (9.8 m/s^2), and θ is the angle of the ramp. In this case, θ = 30 degrees and m = 40 kg, so the force required would be:

F = (40 kg)(9.8 m/s^2)(sin 30 degrees) = 196 N

This means that a force of 196 N must be applied to the mass in order to keep it sliding down the ramp at a constant velocity. This is because the force of gravity acting on the mass is balanced by the force applied along the ramp, resulting in a net force of zero and a constant velocity. Since the ramp is frictionless, there is no additional force acting against the mass.
 

1. What is the formula for calculating the force needed to push a mass down an inclined plane?

The formula for calculating the force needed to push a mass down an inclined plane is F = mgsinθ, where F is the force, m is the mass, g is the acceleration due to gravity, and θ is the angle of the incline.

2. How does the angle of the incline affect the force required to push a mass down an inclined plane?

The force required to push a mass down an inclined plane increases as the angle of the incline increases. This is because a steeper incline requires a greater force to overcome the force of gravity pulling the mass down the incline.

3. Is the force required to push a mass down an inclined plane affected by the mass of the object?

Yes, the force required to push a mass down an inclined plane is directly proportional to the mass of the object. This means that as the mass increases, the force required to push it down the incline also increases.

4. How does the force required to push a mass down an inclined plane differ from the force required to lift the same mass vertically?

The force required to push a mass down an inclined plane is less than the force required to lift the same mass vertically. This is because the angle of the incline reduces the amount of force needed to overcome the force of gravity.

5. Can the force required to push a mass down an inclined plane be reduced?

Yes, the force required to push a mass down an inclined plane can be reduced by using a longer incline or by using a smaller mass. Additionally, using a lubricant on the incline can also reduce the force needed to push the mass down.

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